Series Program
In c language you can print any number series. Here i will show you how to print number series in c language with explanation. In case of print number series you need to focus on common difference between two numbers..
C program to Calculate [(1^1)/1] + [(2^2)/2] + [(3^3)/3] + [(4^4)/4] + [(5^5)/5] + ... + [(n^n)/n] series
#include<stdio.h> #include<math.h> long power(int a, int b) { long i, p=1; for(i=1;i<=b;i++) { p=p*a; } return p; } int main() { long i,n; double sum=0; n=5; for(i=1;i<=n;i++) { sum=sum+(power(i,i)/i); } printf("Sum: %lf",sum); return 0; }
Output:
sum: 701.000000
#include <stdio.h> #include <stdlib.h> #include <math.h> long power(int a, int b) { long i, p=1; for(i=1;i<=b;i++) { p=p*a; } return p; } int main() { long i,n; double sum=0; printf("\n Enter n value [(1^1)/1] + [(2^2)/2] + [(3^3)/3] + [(4^4)/4] + [(5^5)/5] + ... + [(n^n)/n]:"); scanf("%d",&n); for(i=1;i<=n;i++) { sum=sum+(power(i,i)/i); } printf("Sum: %lf",sum); return 0; }