C++ Program to calculate (a - b)4. | C++ Program to calculate 'a' minus 'b' hole to the power of four. | सी ++ प्रोग्राम चार की शक्ति के लिए 'एक' शून्य 'बी' छेद की गणना करने के लिए।

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C++ Program to calculate (a - b)4.

Let see the program to calculate (a - b)4.


Example:

    

  1. To calculate (a - b)4.
    2. 

  2. Formula: (a - b)4 = a4 - 4a3 + 6a2b2 - 4ab3 + b4
    3. 

  3. Input a=1,b=2
    4. 

  4. (a - b)4 =1
    5. 





#include <iostream>

using namespace std;
int main(void)
{
    int a,b,result;
    cout<<"Enter a value :";
    cin>>a;
    cout<<"Enter b value :";
    cin>>b;
    result= a*a*a*a - 4*a*a*a*b + 6*a*a*b*b - 4*a*b*b*b + b*b*b*b ;
    cout<<" Result (a - b)^4 = :"<<result<<endl;
    return 0;
}
Output:

 Enter a value :2
 Enter b value :5

 Result (a - b)^4 = :81



/* C++ Program to calculate (a-b)4 using pow() function. */
#include <iostream>

using namespace std;
#include <math.h>
int main(void)
{
    int a,b,result;
    cout<<"Enter a value :";
    cin>>a;
    cout<<"Enter b value :";
    cin>>b;
    result= pow(a,4) - 4*pow(a,3)*b + 6*pow(a,2)*pow(b,2) - 4*a*pow(b,3) + pow(b,4) ;
    cout<<" Result (a - b)^4 = :"<<result<<endl;
    return 0;
}
Output:

 Enter a value :1
 Enter b value :3

 Result (a - b)^4 = :16

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